10x^2=25=0

Solution for 10x^2=25=0 equation:

10x^2=25=0

We move all terms to the left:

10x^2-(25)=0

a = 10; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·10·(-25)
Δ = 1000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1000}=\sqrt{100*10}=\sqrt{100}*\sqrt{10}=10\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{10}}{2*10}=\frac{0-10\sqrt{10}}{20}
=-\frac{10\sqrt{10}}{20}
=-\frac{\sqrt{10}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{10}}{2*10}=\frac{0+10\sqrt{10}}{20}
=\frac{10\sqrt{10}}{20}
=\frac{\sqrt{10}}{2}
$